Abstract
For n∈N let δn be the smallest value such that every graph of order n and minimum degree at least δn admits an orientation of diameter two. We show that δn=[Formula presented]+Θ(lnn).
| Original language | English |
|---|---|
| Pages (from-to) | 1063-1065 |
| Number of pages | 3 |
| Journal | Discrete Mathematics |
| Volume | 342 |
| Issue number | 4 |
| DOIs | |
| Publication status | Published - Apr 2019 |
Keywords
- Diameter
- Distance
- Minimum degree
- Orientation
- Oriented diameter
ASJC Scopus subject areas
- Theoretical Computer Science
- Discrete Mathematics and Combinatorics